What is the integral of (4sin(x)-3cos(x)) ?

The integral of (4sin(x)-3cos(x)) is -4cos(x)-3sin(x)+C

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integral of (4sin(x)-3cos(x))

\int (4 sin (x) - 3 cos (x)) d x

- 4 cos (x) - 3 sin (x) + C

Solution steps

\int 4 sin (x) - 3 cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 sin (x) d x - \int 3 cos (x) d x

\int 4 sin (x) d x = - 4 cos (x)

\int 3 cos (x) d x = 3 sin (x)

= - 4 cos (x) - 3 sin (x)

Add a constant to the solution

= - 4 cos (x) - 3 sin (x) + C

\int 6 e^{- 7 x} d x

\int \frac{u}{- u ^{2} + 9} d u

\int x^{4} + 2 x d x

\int (x^{2} - e^{2 x}) d x

\int 4 x^{2} + 2 d x

What is the integral of (4sin(x)-3cos(x)) ?
The integral of (4sin(x)-3cos(x)) is -4cos(x)-3sin(x)+C