What is the integral of sec(21x)tan(21x) ?

The integral of sec(21x)tan(21x) is 1/21 sec(21x)+C

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integral of sec(21x)tan(21x)

\int sec (21 x) tan (21 x) d x

\frac{1}{21} sec (21 x) + C

Solution steps

\int sec (21 x) tan (21 x) d x

Apply u-substitution

: \int \frac{1}{21} d u

= \int \frac{1}{21} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{21} u

Substitute back

u = sec (21 x)

= \frac{1}{21} sec (21 x)

Add a constant to the solution

= \frac{1}{21} sec (21 x) + C

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\int 3 x (x + 4) d x

\int \frac{x - 2}{x ^{2} ( x + 1 )} d x

What is the integral of sec(21x)tan(21x) ?
The integral of sec(21x)tan(21x) is 1/21 sec(21x)+C