What is the integral of (e^x)/(-8+e^x) ?

The integral of (e^x)/(-8+e^x) is ln|-8+e^x|+C

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integral of (e^x)/(-8+e^x)

\int \frac{e ^{x}}{- 8 + e ^{x}} d x

ln ∣ - 8 + e^{x} ∣ + C

Solution steps

\int \frac{e ^{x}}{- 8 + e ^{x}} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = - 8 + e^{x}

= ln ∣ - 8 + e^{x} ∣

Add a constant to the solution

= ln ∣ - 8 + e^{x} ∣ + C

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What is the integral of (e^x)/(-8+e^x) ?
The integral of (e^x)/(-8+e^x) is ln|-8+e^x|+C