What is (\partial)/(\partial x)(cos(x+y)) ?

The answer to (\partial)/(\partial x)(cos(x+y)) is -sin(x+y)

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(\partial)/(\partial x)(cos(x+y))

\frac{\partial}{\partial x} (cos (x + y))

- sin (x + y)

Solution steps

\frac{\partial}{\partial x} (cos (x + y))

Treat

y

as a constant

Apply the chain rule:

- sin (x + y) \frac{\partial}{\partial x} (x + y)

= - sin (x + y) \frac{\partial}{\partial x} (x + y)

\frac{\partial}{\partial x} (x + y) = 1

= - sin (x + y) \cdot 1

Simplify

= - sin (x + y)

\int (2 x - 1) d x

- \frac{3}{x}

\frac{d}{d x} (a cos^{2} (x))

n = 0 \sum \infty 4

\frac{\partial}{\partial x} ((x^{2} + y^{2})^{3})

What is (\partial)/(\partial x)(cos(x+y)) ?
The answer to (\partial)/(\partial x)(cos(x+y)) is -sin(x+y)