What is the integral of 0.9x^2+2x ?

The integral of 0.9x^2+2x is 0.3x^3+x^2+C

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integral of 0.9x^2+2x

\int 0.9 x^{2} + 2 x d x

0.3 x^{3} + x^{2} + C

Solution steps

\int 0.9 x^{2} + 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 0.9 x^{2} d x + \int 2 x d x

\int 0.9 x^{2} d x = 0.3 x^{3}

\int 2 x d x = x^{2}

= 0.3 x^{3} + x^{2}

Add a constant to the solution

= 0.3 x^{3} + x^{2} + C

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