What is the integral of cos(tan(x))sec^2(x) ?

The integral of cos(tan(x))sec^2(x) is sin(tan(x))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of cos(tan(x))sec^2(x)

\int cos (tan (x)) sec^{2} (x) d x

sin (tan (x)) + C

Solution steps

\int cos (tan (x)) sec^{2} (x) d x

Apply u-substitution

: \int cos (u) d u

= \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= sin (u)

Substitute back

u = tan (x)

= sin (tan (x))

Add a constant to the solution

= sin (tan (x)) + C

\int 68 x^{- \frac{1}{5}} tan (x^{\frac{4}{5}}) d x

\int \frac{1}{4 t ^{3}} d t

\int \frac{8}{x + 2} d x

\int \frac{1}{2} sin^{2} (2 x) d x

\int x^{2} arcsec (x) d x

What is the integral of cos(tan(x))sec^2(x) ?
The integral of cos(tan(x))sec^2(x) is sin(tan(x))+C