What is the integral of 1/2 x^{-26} ?

The integral of 1/2 x^{-26} is -1/(50x^{25)}+C

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integral of 1/2 x^{-26}

\int \frac{1}{2} x^{- 26} d x

- \frac{1}{50 x ^{25}} + C

Solution steps

\int \frac{1}{2} x^{- 26} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int x^{- 26} d x

Apply the Power Rule

: - \frac{1}{25 x ^{25}}

= \frac{1}{2} (- \frac{1}{25 x ^{25}})

Simplify

\frac{1}{2} (- \frac{1}{25 x ^{25}}) : - \frac{1}{50 x ^{25}}

= - \frac{1}{50 x ^{25}}

Add a constant to the solution

= - \frac{1}{50 x ^{25}} + C

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What is the integral of 1/2 x^{-26} ?
The integral of 1/2 x^{-26} is -1/(50x^{25)}+C