Solution
Solution
Solution steps
Apply u-substitution
Take the constant out:
Apply u-substitution
Use the common integral:
Substitute back
Simplify
Add a constant to the solution
Popular Examples
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Frequently Asked Questions (FAQ)
What is the integral of 1/((9-4x)sqrt(16x^2-72x+80)) ?
The integral of 1/((9-4x)sqrt(16x^2-72x+80)) is -1/4 arctan(sqrt(16x^2-72x+80))+C