What is the integral of 1/100 e^{-x/(100)} ?

The integral of 1/100 e^{-x/(100)} is -e^{-x/(100)}+C

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integral of 1/100 e^{-x/(100)}

\int \frac{1}{100} e^{- \frac{x}{100}} d x

- e^{- \frac{x}{100}} + C

Solution steps

\int \frac{1}{100} e^{- \frac{x}{100}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{100} \cdot \int e^{- \frac{x}{100}} d x

Apply u-substitution

: \int - 100 e^{u} d u

= \frac{1}{100} \cdot \int - 100 e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{100} (- 100 \cdot \int e^{u} d u)

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{100} (- 100 e^{u})

Substitute back

u = - \frac{x}{100}

= \frac{1}{100} (- 100 e^{- \frac{x}{100}})

Simplify

\frac{1}{100} (- 100 e^{- \frac{x}{100}}) : - e^{- \frac{x}{100}}

= - e^{- \frac{x}{100}}

Add a constant to the solution

= - e^{- \frac{x}{100}} + C

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What is the integral of 1/100 e^{-x/(100)} ?
The integral of 1/100 e^{-x/(100)} is -e^{-x/(100)}+C