What is the integral of (2x+3)/(5+4x+4x^2) ?

The integral of (2x+3)/(5+4x+4x^2) is 1/4 ln|4x^2+4x+5|+1/2 arctan(x+1/2)+C

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integral of (2x+3)/(5+4x+4x^2)

\int \frac{2 x + 3}{5 + 4 x + 4 x ^{2}} d x

\frac{1}{4} ln 4 x^{2} + 4 x + 5 + \frac{1}{2} arctan (x + \frac{1}{2}) + C

Solution steps

\int \frac{2 x + 3}{5 + 4 x + 4 x ^{2}} d x

Expand

\frac{2 x + 3}{5 + 4 x + 4 x ^{2}} : \frac{2 x}{5 + 4 x + 4 x ^{2}} + \frac{3}{5 + 4 x + 4 x ^{2}}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2 x}{5 + 4 x + 4 x ^{2}} d x + \int \frac{3}{5 + 4 x + 4 x ^{2}} d x

\int \frac{2 x}{5 + 4 x + 4 x ^{2}} d x = \frac{1}{4} ln 4 x^{2} + 4 x + 5 - \frac{1}{4} arctan (x + \frac{1}{2})

\int \frac{3}{5 + 4 x + 4 x ^{2}} d x = \frac{3}{4} arctan (x + \frac{1}{2})

= \frac{1}{4} ln 4 x^{2} + 4 x + 5 - \frac{1}{4} arctan (x + \frac{1}{2}) + \frac{3}{4} arctan (x + \frac{1}{2})

Add similar elements:

- \frac{1}{4} arctan (x + \frac{1}{2}) + \frac{3}{4} arctan (x + \frac{1}{2}) = \frac{1}{2} arctan (x + \frac{1}{2})

= \frac{1}{4} ln 4 x^{2} + 4 x + 5 + \frac{1}{2} arctan (x + \frac{1}{2})

Add a constant to the solution

= \frac{1}{4} ln 4 x^{2} + 4 x + 5 + \frac{1}{2} arctan (x + \frac{1}{2}) + C

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What is the integral of (2x+3)/(5+4x+4x^2) ?
The integral of (2x+3)/(5+4x+4x^2) is 1/4 ln|4x^2+4x+5|+1/2 arctan(x+1/2)+C