What is the integral of (ln^4(z))/z ?

The integral of (ln^4(z))/z is (ln^5(z))/5+C

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integral of (ln^4(z))/z

\int \frac{ln ^{4} ( z )}{z} d z

\frac{ln ^{5} ( z )}{5} + C

Solution steps

\int \frac{ln ^{4} ( z )}{z} d z

Apply u-substitution

: \int u^{4} d u

= \int u^{4} d u

Apply the Power Rule

: \frac{u ^{5}}{5}

= \frac{u ^{5}}{5}

Substitute back

u = ln (z)

= \frac{ln ^{5} ( z )}{5}

Add a constant to the solution

= \frac{ln ^{5} ( z )}{5} + C

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What is the integral of (ln^4(z))/z ?
The integral of (ln^4(z))/z is (ln^5(z))/5+C