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Popular >

integral of 6(1-y)

Solution

\int 6 (1 - y) d y

Solution

6 (y - \frac{y ^{2}}{2}) + C

Solution steps

\int 6 (1 - y) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int 1 - y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 6 (\int 1 d y - \int y d y)

\int 1 d y = y

\int y d y = \frac{y ^{2}}{2}

= 6 (y - \frac{y ^{2}}{2})

Add a constant to the solution

= 6 (y - \frac{y ^{2}}{2}) + C

Graph

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\int e^{4 x} + x x d x

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\int (x + x^{3}) d x

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\int \frac{7 sin ( x )}{cos ^{2} ( x )} d x

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\int (a - x) a + x d x

integral of e^{3x}+5e^{-x}

\int e^{3 x} + 5 e^{- x} d x

Frequently Asked Questions (FAQ)

What is the integral of 6(1-y) ?
The integral of 6(1-y) is 6(y-(y^2)/2)+C