What is the integral of x^6ln(4x) ?

The integral of x^6ln(4x) is 1/7 x^7ln(4x)-(x^7)/(49)+C

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integral of x^6ln(4x)

\int x^{6} ln (4 x) d x

\frac{1}{7} x^{7} ln (4 x) - \frac{x ^{7}}{49} + C

Solution steps

\int x^{6} ln (4 x) d x

Apply Integration By Parts

: \frac{1}{7} x^{7} ln (4 x) - \int \frac{x ^{6}}{7} d x

= \frac{1}{7} x^{7} ln (4 x) - \int \frac{x ^{6}}{7} d x

\int \frac{x ^{6}}{7} d x = \frac{x ^{7}}{49}

= \frac{1}{7} x^{7} ln (4 x) - \frac{x ^{7}}{49}

Add a constant to the solution

= \frac{1}{7} x^{7} ln (4 x) - \frac{x ^{7}}{49} + C

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What is the integral of x^6ln(4x) ?
The integral of x^6ln(4x) is 1/7 x^7ln(4x)-(x^7)/(49)+C