What is the integral of (x+1)/(x(x-2)) ?

The integral of (x+1)/(x(x-2)) is -1/2 ln|x|+3/2 ln|x-2|+C

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integral of (x+1)/(x(x-2))

\int \frac{x + 1}{x ( x - 2 )} d x

- \frac{1}{2} ln ∣ x ∣ + \frac{3}{2} ln ∣ x - 2 ∣ + C

Solution steps

\int \frac{x + 1}{x ( x - 2 )} d x

Expand

\frac{x + 1}{x ( x - 2 )} : \frac{x}{x ( x - 2 )} + \frac{1}{x ( x - 2 )}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x}{x ( x - 2 )} d x + \int \frac{1}{x ( x - 2 )} d x

\int \frac{x}{x ( x - 2 )} d x = ln ∣ x - 2 ∣

\int \frac{1}{x ( x - 2 )} d x = - \frac{1}{2} ln ∣ x ∣ + \frac{1}{2} ln ∣ x - 2 ∣

= ln ∣ x - 2 ∣ - \frac{1}{2} ln ∣ x ∣ + \frac{1}{2} ln ∣ x - 2 ∣

Simplify

ln ∣ x - 2 ∣ - \frac{1}{2} ln ∣ x ∣ + \frac{1}{2} ln ∣ x - 2 ∣ : - \frac{1}{2} ln ∣ x ∣ + \frac{3}{2} ln ∣ x - 2 ∣

= - \frac{1}{2} ln ∣ x ∣ + \frac{3}{2} ln ∣ x - 2 ∣

Add a constant to the solution

= - \frac{1}{2} ln ∣ x ∣ + \frac{3}{2} ln ∣ x - 2 ∣ + C

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What is the integral of (x+1)/(x(x-2)) ?
The integral of (x+1)/(x(x-2)) is -1/2 ln|x|+3/2 ln|x-2|+C