What is the integral of (1-cos(4x)) ?

The integral of (1-cos(4x)) is x-1/4 sin(4x)+C

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integral of (1-cos(4x))

\int (1 - cos (4 x)) d x

x - \frac{1}{4} sin (4 x) + C

Solution steps

\int 1 - cos (4 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d x - \int cos (4 x) d x

\int 1 d x = x

\int cos (4 x) d x = \frac{1}{4} sin (4 x)

= x - \frac{1}{4} sin (4 x)

Add a constant to the solution

= x - \frac{1}{4} sin (4 x) + C

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What is the integral of (1-cos(4x)) ?
The integral of (1-cos(4x)) is x-1/4 sin(4x)+C