What is the integral of 1/(x^{2-1)} ?

The integral of 1/(x^{2-1)} is ln|x|+C

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integral of 1/(x^{2-1)}

\int \frac{1}{x ^{2 - 1}} d x

ln ∣ x ∣ + C

Solution steps

\int \frac{1}{x ^{2 - 1}} d x

Simplify

= \int \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= ln ∣ x ∣

Add a constant to the solution

= ln ∣ x ∣ + C

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