What is the integral of 5x^4+3x^3-2 ?

The integral of 5x^4+3x^3-2 is x^5+(3x^4)/4-2x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 5x^4+3x^3-2

\int 5 x^{4} + 3 x^{3} - 2 d x

x^{5} + \frac{3 x ^{4}}{4} - 2 x + C

Solution steps

\int 5 x^{4} + 3 x^{3} - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 x^{4} d x + \int 3 x^{3} d x - \int 2 d x

\int 5 x^{4} d x = x^{5}

\int 3 x^{3} d x = \frac{3 x ^{4}}{4}

\int 2 d x = 2 x

= x^{5} + \frac{3 x ^{4}}{4} - 2 x

Add a constant to the solution

= x^{5} + \frac{3 x ^{4}}{4} - 2 x + C

\int \frac{( 6 - 6 x )}{( 6 x - 3 x ^{2} )} d x

\int \frac{x - 5}{x ^{2} + 4} d x

\int sin^{3} (\frac{x}{a}) cos^{3} (\frac{x}{a}) d x

\int \frac{4}{x + 1 + x} d x

\int \frac{x ^{3} + 4 x - 3}{x} d x

What is the integral of 5x^4+3x^3-2 ?
The integral of 5x^4+3x^3-2 is x^5+(3x^4)/4-2x+C