What is the integral of-1/(sqrt(1+x^2)) ?

The integral of-1/(sqrt(1+x^2)) is -ln|sqrt(x^2+1)+x|+C

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integral of-1/(sqrt(1+x^2))

\int - \frac{1}{1 + x ^{2}} d x

- ln x^{2} + 1 + x + C

Solution steps

\int - \frac{1}{1 + x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = ln x^{2} + 1 + x

= - ln x^{2} + 1 + x

Add a constant to the solution

= - ln x^{2} + 1 + x + C

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What is the integral of-1/(sqrt(1+x^2)) ?
The integral of-1/(sqrt(1+x^2)) is -ln|sqrt(x^2+1)+x|+C