What is the integral of 9e^{9x}sin(e^{9x}) ?

The integral of 9e^{9x}sin(e^{9x}) is -cos(e^{9x})+C

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integral of 9e^{9x}sin(e^{9x})

\int 9 e^{9 x} sin (e^{9 x}) d x

- cos (e^{9 x}) + C

Solution steps

\int 9 e^{9 x} sin (e^{9 x}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int e^{9 x} sin (e^{9 x}) d x

Apply u-substitution

: \int \frac{sin ( u )}{9} d u

= 9 \cdot \int \frac{sin ( u )}{9} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \frac{1}{9} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= 9 \cdot \frac{1}{9} (- cos (u))

Substitute back

u = e^{9 x}

= 9 \cdot \frac{1}{9} (- cos (e^{9 x}))

Simplify

9 \cdot \frac{1}{9} (- cos (e^{9 x})) : - cos (e^{9 x})

= - cos (e^{9 x})

Add a constant to the solution

= - cos (e^{9 x}) + C

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What is the integral of 9e^{9x}sin(e^{9x}) ?
The integral of 9e^{9x}sin(e^{9x}) is -cos(e^{9x})+C