What is the solution for (dV)/(12-2V)=dt,V(0)=1 ?

The solution for (dV)/(12-2V)=dt,V(0)=1 is V(t)=-(e^{-2t-c_{1}})/2+6

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(dV)/(12-2V)=dt,V(0)=1

\frac{d V}{12 - 2 V} = d t, V (0) = 1

V (t) = - \frac{e ^{- 2 t - c_{1}}}{2} + 6

Solution steps

\frac{d V ( t )}{12 - 2 V ( t )} = d t

Solve separable ODE:

V (t) = - \frac{e ^{- 2 t - c_{1}}}{2} + 6

V (t) = - \frac{e ^{- 2 t - c_{1}}}{2} + 6

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What is the solution for (dV)/(12-2V)=dt,V(0)=1 ?
The solution for (dV)/(12-2V)=dt,V(0)=1 is V(t)=-(e^{-2t-c_{1}})/2+6