What is the integral of 1/(3\sqrt[3]{x^4)} ?

The integral of 1/(3\sqrt[3]{x^4)} is -1/(\sqrt[3]{x)}+C

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integral of 1/(3\sqrt[3]{x^4)}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

= \frac{1}{3} \cdot \int \frac{1}{x ^{\frac{4}{3}}} d x

Apply the Power Rule

Simplify

Add a constant to the solution

\int (x - sin (x) + cos (x)) d x

\int \frac{1}{( a - x )} d x

\int \frac{2 x + 3}{x ^{2} - x} d x

\int \frac{t}{4 - t ^{4}} d t

3 x - 4

What is the integral of 1/(3\sqrt[3]{x^4)} ?
The integral of 1/(3\sqrt[3]{x^4)} is -1/(\sqrt[3]{x)}+C