What is the integral of 6/(θ^2)cos(6/θ) ?

The integral of 6/(θ^2)cos(6/θ) is -sin(6/θ)+C

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integral of 6/(θ^2)cos(6/θ)

\int \frac{6}{θ ^{2}} cos (\frac{6}{θ}) d θ

- sin (\frac{6}{θ}) + C

Solution steps

\int \frac{6}{θ ^{2}} cos (\frac{6}{θ}) d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int \frac{1}{θ ^{2}} cos (\frac{6}{θ}) d θ

Apply u-substitution

: \int - \frac{cos ( u )}{6} d u

= 6 \cdot \int - \frac{cos ( u )}{6} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 (- \frac{1}{6} \cdot \int cos (u) d u)

Use the common integral:

\int cos (u) d u = sin (u)

= 6 (- \frac{1}{6} sin (u))

Substitute back

u = \frac{6}{θ}

= 6 (- \frac{1}{6} sin (\frac{6}{θ}))

Simplify

6 (- \frac{1}{6} sin (\frac{6}{θ})) : - sin (\frac{6}{θ})

= - sin (\frac{6}{θ})

Add a constant to the solution

= - sin (\frac{6}{θ}) + C

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What is the integral of 6/(θ^2)cos(6/θ) ?
The integral of 6/(θ^2)cos(6/θ) is -sin(6/θ)+C