What is the integral of (tan(x))/(1+cos^2(x)) ?

The integral of (tan(x))/(1+cos^2(x)) is 1/2 ln|tan^2(x)+2|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (tan(x))/(1+cos^2(x))

\int \frac{tan ( x )}{1 + cos ^{2} ( x )} d x

\frac{1}{2} ln tan^{2} (x) + 2 + C

Solution steps

\int \frac{tan ( x )}{1 + cos ^{2} ( x )} d x

Apply Trigonometric Substitution

: \int \frac{u}{u ^{2} + 2} d u

= \int \frac{u}{u ^{2} + 2} d u

Apply u-substitution

: \int \frac{1}{2 v} d v

= \int \frac{1}{2 v} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{v} d v

Use the common integral:

\int \frac{1}{v} d v = ln (∣ v ∣)

= \frac{1}{2} ln ∣ v ∣

Substitute back

= \frac{1}{2} ln tan^{2} (x) + 2

Add a constant to the solution

= \frac{1}{2} ln tan^{2} (x) + 2 + C

\int x 2 - 3 x^{2} d x

\int (tan (x) + 1) d x

\int 2 x^{- \frac{1}{7}} + 8 d x

\int \frac{4}{sec ( x ) - 1} d x

\int 2 x^{4} + 3 x + \frac{1}{x ^{3}} d x

What is the integral of (tan(x))/(1+cos^2(x)) ?
The integral of (tan(x))/(1+cos^2(x)) is 1/2 ln|tan^2(x)+2|+C