What is the integral of (x+4)/2 ?

The integral of (x+4)/2 is 1/2 ((x^2)/2+4x)+C

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integral of (x+4)/2

\int \frac{x + 4}{2} d x

\frac{1}{2} (\frac{x ^{2}}{2} + 4 x) + C

Solution steps

\int \frac{x + 4}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int x d x + \int 4 d x)

\int x d x = \frac{x ^{2}}{2}

\int 4 d x = 4 x

= \frac{1}{2} (\frac{x ^{2}}{2} + 4 x)

Add a constant to the solution

= \frac{1}{2} (\frac{x ^{2}}{2} + 4 x) + C

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