What is the integral of x^3ln(4x^2) ?

The integral of x^3ln(4x^2) is 1/2 x^4ln(2x)-(x^4)/8+C

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integral of x^3ln(4x^2)

\int x^{3} ln (4 x^{2}) d x

\frac{1}{2} x^{4} ln (2 x) - \frac{x ^{4}}{8} + C

Solution steps

\int x^{3} ln (4 x^{2}) d x

Apply Integration By Parts

: \frac{1}{4} x^{4} ln (4 x^{2}) - \int \frac{x ^{3}}{2} d x

= \frac{1}{4} x^{4} ln (4 x^{2}) - \int \frac{x ^{3}}{2} d x

\int \frac{x ^{3}}{2} d x = \frac{x ^{4}}{8}

= \frac{1}{4} x^{4} ln (4 x^{2}) - \frac{x ^{4}}{8}

\frac{1}{4} x^{4} ln (4 x^{2}) = \frac{1}{2} x^{4} ln (2 x)

= \frac{1}{2} x^{4} ln (2 x) - \frac{x ^{4}}{8}

Add a constant to the solution

= \frac{1}{2} x^{4} ln (2 x) - \frac{x ^{4}}{8} + C

\int \frac{1}{ln ( x - 1 )} d x

\int \frac{1}{x ^{2} 2 - 3 x} d x

\int (\frac{1 + ln ( x )}{x}) d x

\int (\frac{1 + x ^{2}}{x}) d x

\int x a + b x d x

What is the integral of x^3ln(4x^2) ?
The integral of x^3ln(4x^2) is 1/2 x^4ln(2x)-(x^4)/8+C