What is the integral of (3x^5-5x^2-3x) ?

The integral of (3x^5-5x^2-3x) is (x^6)/2-(5x^3)/3-(3x^2)/2+C

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integral of (3x^5-5x^2-3x)

\int (3 x^{5} - 5 x^{2} - 3 x) d x

\frac{x ^{6}}{2} - \frac{5 x ^{3}}{3} - \frac{3 x ^{2}}{2} + C

Solution steps

\int 3 x^{5} - 5 x^{2} - 3 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{5} d x - \int 5 x^{2} d x - \int 3 x d x

\int 3 x^{5} d x = \frac{x ^{6}}{2}

\int 5 x^{2} d x = \frac{5 x ^{3}}{3}

\int 3 x d x = \frac{3 x ^{2}}{2}

= \frac{x ^{6}}{2} - \frac{5 x ^{3}}{3} - \frac{3 x ^{2}}{2}

Add a constant to the solution

= \frac{x ^{6}}{2} - \frac{5 x ^{3}}{3} - \frac{3 x ^{2}}{2} + C

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What is the integral of (3x^5-5x^2-3x) ?
The integral of (3x^5-5x^2-3x) is (x^6)/2-(5x^3)/3-(3x^2)/2+C