What is the integral of 2sin(x)-2cos(2x) ?

The integral of 2sin(x)-2cos(2x) is -2cos(x)-sin(2x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 2sin(x)-2cos(2x)

\int 2 sin (x) - 2 cos (2 x) d x

- 2 cos (x) - sin (2 x) + C

Solution steps

\int 2 sin (x) - 2 cos (2 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 sin (x) d x - \int 2 cos (2 x) d x

\int 2 sin (x) d x = - 2 cos (x)

\int 2 cos (2 x) d x = sin (2 x)

= - 2 cos (x) - sin (2 x)

Add a constant to the solution

= - 2 cos (x) - sin (2 x) + C

\int \frac{1}{x ( ln ( x ^{4} ) ) ^{8}} d x

\int (16 x + 1) 8 x^{2} + x d x

\int \frac{4 x + 1}{x ^{2} + 2 x + 2} d x

\int x^{6} e^{(x^{7} - 4)} d x

\int \frac{- 9 x}{( x + 1 ) - x + 1} d x

What is the integral of 2sin(x)-2cos(2x) ?
The integral of 2sin(x)-2cos(2x) is -2cos(x)-sin(2x)+C