What is the integral of (2x+3)^8 ?

The integral of (2x+3)^8 is 1/18 (2x+3)^9+C

Popular >

integral of (2x+3)^8

\int (2 x + 3)^{8} d x

\frac{1}{18} (2 x + 3)^{9} + C

Solution steps

\int (2 x + 3)^{8} d x

Apply u-substitution

: \int \frac{u ^{8}}{2} d u

= \int \frac{u ^{8}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int u^{8} d u

Apply the Power Rule

: \frac{u ^{9}}{9}

= \frac{1}{2} \cdot \frac{u ^{9}}{9}

Substitute back

u = 2 x + 3

= \frac{1}{2} \cdot \frac{( 2 x + 3 ) ^{9}}{9}

Simplify

\frac{1}{2} \cdot \frac{( 2 x + 3 ) ^{9}}{9} : \frac{1}{18} (2 x + 3)^{9}

= \frac{1}{18} (2 x + 3)^{9}

Add a constant to the solution

= \frac{1}{18} (2 x + 3)^{9} + C

\int \frac{5 x ^{2}}{5 + x ^{3}} d x

\int (sec^{2} (x) - 1)^{2} d x

\int 10 (1 + \frac{x}{60})^{2} d x

\int \frac{1}{5 - 4 y ^{2}} d y

\int \frac{1 + x ^{2}}{x 1 + x ^{2}} d x