What is the integral of (sin(2x))/(sqrt(2-cos(2x))) ?

The integral of (sin(2x))/(sqrt(2-cos(2x))) is sqrt(2-cos(2x))+C

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integral of (sin(2x))/(sqrt(2-cos(2x)))

\int \frac{sin ( 2 x )}{2 - cos ( 2 x )} d x

2 - cos (2 x) + C

Solution steps

\int \frac{sin ( 2 x )}{2 - cos ( 2 x )} d x

Apply u-substitution

: \int \frac{sin ( u )}{2 2 - cos ( u )} d u

= \int \frac{sin ( u )}{2 2 - cos ( u )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{sin ( u )}{2 - cos ( u )} d u

Apply u-substitution

: \int \frac{1}{v} d v

= \frac{1}{2} \cdot \int \frac{1}{v} d v

Apply the Power Rule

: 2 v^{\frac{1}{2}}

= \frac{1}{2} \cdot 2 v^{\frac{1}{2}}

Substitute back

= \frac{1}{2} \cdot 2 (2 - cos (2 x))^{\frac{1}{2}}

Simplify

\frac{1}{2} \cdot 2 (2 - cos (2 x))^{\frac{1}{2}} : 2 - cos (2 x)

= 2 - cos (2 x)

Add a constant to the solution

= 2 - cos (2 x) + C

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What is the integral of (sin(2x))/(sqrt(2-cos(2x))) ?
The integral of (sin(2x))/(sqrt(2-cos(2x))) is sqrt(2-cos(2x))+C