What is the integral of (38-5x)-28 ?

The integral of (38-5x)-28 is -(5x^2)/2+10x+C

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integral of (38-5x)-28

\int (38 - 5 x) - 28 d x

- \frac{5 x ^{2}}{2} + 10 x + C

Solution steps

\int 38 - 5 x - 28 d x

Simplify

= \int - 5 x + 10 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 5 x d x + \int 10 d x

\int 5 x d x = \frac{5 x ^{2}}{2}

\int 10 d x = 10 x

= - \frac{5 x ^{2}}{2} + 10 x

Add a constant to the solution

= - \frac{5 x ^{2}}{2} + 10 x + C

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What is the integral of (38-5x)-28 ?
The integral of (38-5x)-28 is -(5x^2)/2+10x+C