What is the integral of (y+3)/(y-2) ?

The integral of (y+3)/(y-2) is y-2+5ln|y-2|+C

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integral of (y+3)/(y-2)

\int \frac{y + 3}{y - 2} d y

y - 2 + 5 ln ∣ y - 2 ∣ + C

Solution steps

\int \frac{y + 3}{y - 2} d y

Apply u-substitution

: \int \frac{u + 5}{u} d u

= \int \frac{u + 5}{u} d u

Expand

\frac{u + 5}{u} : 1 + \frac{5}{u}

= \int 1 + \frac{5}{u} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d u + \int \frac{5}{u} d u

\int 1 d u = u

\int \frac{5}{u} d u = 5 ln ∣ u ∣

= u + 5 ln ∣ u ∣

Substitute back

u = y - 2

= y - 2 + 5 ln ∣ y - 2 ∣

Add a constant to the solution

= y - 2 + 5 ln ∣ y - 2 ∣ + C

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What is the integral of (y+3)/(y-2) ?
The integral of (y+3)/(y-2) is y-2+5ln|y-2|+C