What is the derivative of 4(5-7x^5) ?

The derivative of 4(5-7x^5) is -140(5-7x)^4

What is the first derivative of 4(5-7x^5) ?

The first derivative of 4(5-7x^5) is -140(5-7x)^4

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\frac{d}{d x} (4 (5 - 7 x)^{5})

- 140 (5 - 7 x)^{4}

Solution steps

\frac{d}{d x} (4 (5 - 7 x)^{5})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} ((5 - 7 x)^{5})

Apply the chain rule:

5 (5 - 7 x)^{4} \frac{d}{d x} (5 - 7 x)

= 5 (5 - 7 x)^{4} \frac{d}{d x} (5 - 7 x)

\frac{d}{d x} (5 - 7 x) = - 7

= 4 \cdot 5 (5 - 7 x)^{4} (- 7)

Simplify

= - 140 (5 - 7 x)^{4}

f (x) = \frac{3}{( x + 1 ) ^{2}}

e^{- 5 x^{4}}

\frac{d}{d x} (2^{arcsech (x)})

\int \frac{x}{x ^{4} + 3} d x

\frac{12 s + 8}{( s - 1 ) ^{5}}

What is the derivative of 4(5-7x^5) ?
The derivative of 4(5-7x^5) is -140(5-7x)^4
What is the first derivative of 4(5-7x^5) ?
The first derivative of 4(5-7x^5) is -140(5-7x)^4