What is the integral of ((3x-1))/(x^2-2x+2) ?

The integral of ((3x-1))/(x^2-2x+2) is 3/2 ln|x^2-2x+2|+2arctan(x-1)+C

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integral of ((3x-1))/(x^2-2x+2)

\int \frac{( 3 x - 1 )}{x ^{2} - 2 x + 2} d x

\frac{3}{2} ln x^{2} - 2 x + 2 + 2 arctan (x - 1) + C

Solution steps

\int \frac{3 x - 1}{x ^{2} - 2 x + 2} d x

Expand

\frac{3 x - 1}{x ^{2} - 2 x + 2} : \frac{3 x}{x ^{2} - 2 x + 2} - \frac{1}{x ^{2} - 2 x + 2}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{3 x}{x ^{2} - 2 x + 2} d x - \int \frac{1}{x ^{2} - 2 x + 2} d x

\int \frac{3 x}{x ^{2} - 2 x + 2} d x = 3 (\frac{1}{2} ln x^{2} - 2 x + 2 + arctan (x - 1))

\int \frac{1}{x ^{2} - 2 x + 2} d x = arctan (x - 1)

= 3 (\frac{1}{2} ln x^{2} - 2 x + 2 + arctan (x - 1)) - arctan (x - 1)

Simplify

3 (\frac{1}{2} ln x^{2} - 2 x + 2 + arctan (x - 1)) - arctan (x - 1) : \frac{3}{2} ln x^{2} - 2 x + 2 + 2 arctan (x - 1)

= \frac{3}{2} ln x^{2} - 2 x + 2 + 2 arctan (x - 1)

Add a constant to the solution

= \frac{3}{2} ln x^{2} - 2 x + 2 + 2 arctan (x - 1) + C

\int \frac{( x + 3 ) ( x - 1 )}{4 ( x + 1 )} d x

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\int \frac{2}{x ^{5}} + \frac{1}{x} d x

What is the integral of ((3x-1))/(x^2-2x+2) ?
The integral of ((3x-1))/(x^2-2x+2) is 3/2 ln|x^2-2x+2|+2arctan(x-1)+C