What is the integral of 12x^2-6x+2 ?

The integral of 12x^2-6x+2 is 4x^3-3x^2+2x+C

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integral of 12x^2-6x+2

\int 12 x^{2} - 6 x + 2 d x

4 x^{3} - 3 x^{2} + 2 x + C

Solution steps

\int 12 x^{2} - 6 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 12 x^{2} d x - \int 6 x d x + \int 2 d x

\int 12 x^{2} d x = 4 x^{3}

\int 6 x d x = 3 x^{2}

\int 2 d x = 2 x

= 4 x^{3} - 3 x^{2} + 2 x

Add a constant to the solution

= 4 x^{3} - 3 x^{2} + 2 x + C

\int e^{- 0}

\int \frac{x ^{2} - 3}{x ^{3} - 3 x ^{2} + 3 x - 1} d x

\int 380 - 0.8 q d q

\int \frac{1}{- x ^{2} - 6 x - 6} d x

\int (a + b x)^{k} d x

What is the integral of 12x^2-6x+2 ?
The integral of 12x^2-6x+2 is 4x^3-3x^2+2x+C