What is the integral of (3sqrt(x^5))/2 ?

The integral of (3sqrt(x^5))/2 is 3/7 x^{7/2}+C

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integral of (3sqrt(x^5))/2

\int \frac{3 x ^{5}}{2} d x

\frac{3}{7} x^{\frac{7}{2}} + C

Solution steps

\int \frac{3 x ^{5}}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{3}{2} \cdot \int x^{5} d x

x^{5} = x^{\frac{5}{2}},

assuming

x \geq 0

= \frac{3}{2} \cdot \int x^{\frac{5}{2}} d x

Apply the Power Rule

: \frac{2}{7} x^{\frac{7}{2}}

= \frac{3}{2} \cdot \frac{2}{7} x^{\frac{7}{2}}

Simplify

\frac{3}{2} \cdot \frac{2}{7} x^{\frac{7}{2}} : \frac{3}{7} x^{\frac{7}{2}}

= \frac{3}{7} x^{\frac{7}{2}}

Add a constant to the solution

= \frac{3}{7} x^{\frac{7}{2}} + C

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What is the integral of (3sqrt(x^5))/2 ?
The integral of (3sqrt(x^5))/2 is 3/7 x^{7/2}+C