What is the integral of-3sin(2x+1) ?

The integral of-3sin(2x+1) is 3/2 cos(2x+1)+C

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integral of-3sin(2x+1)

\int - 3 sin (2 x + 1) d x

\frac{3}{2} cos (2 x + 1) + C

Solution steps

\int - 3 sin (2 x + 1) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \int sin (2 x + 1) d x

Apply u-substitution

: \int sin (u) \frac{1}{2} d u

= - 3 \cdot \int sin (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \frac{1}{2} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= - 3 \cdot \frac{1}{2} (- cos (u))

Substitute back

u = 2 x + 1

= - 3 \cdot \frac{1}{2} (- cos (2 x + 1))

Simplify

- 3 \cdot \frac{1}{2} (- cos (2 x + 1)) : \frac{3}{2} cos (2 x + 1)

= \frac{3}{2} cos (2 x + 1)

Add a constant to the solution

= \frac{3}{2} cos (2 x + 1) + C

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What is the integral of-3sin(2x+1) ?
The integral of-3sin(2x+1) is 3/2 cos(2x+1)+C