What is the tangent of f(x)=(2/(x-2)),\at x=4 ?

The tangent of f(x)=(2/(x-2)),\at x=4 is y=-1/2 x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=(2/(x-2)),\at x=4

tangent of

f (x) = (\frac{2}{x - 2}), at x = 4

y = - \frac{1}{2} x + 3

Solution steps

Find the tangent point:

(4, 1)

Find the slope of

f (x) = \frac{2}{x - 2} : \frac{df ( x )}{d x} = - \frac{2}{( x - 2 ) ^{2}}

Compute the slope of

f (x) = \frac{2}{x - 2}

x = 4 : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(4, 1) : y = - \frac{1}{2} x + 3

y = - \frac{1}{2} x + 3

\int_{0}^{l n (3)} \frac{3}{e ^{x} + 2} d x

(x - 2) \frac{d y}{d x} - y = 3

y = 9 x - 8 x, (1, 1)

\frac{( 2 - z ) ^{\frac{2}{3}}}{4 z + 5}

\frac{d}{d x} ((3 x + 2)^{4})

What is the tangent of f(x)=(2/(x-2)),\at x=4 ?
The tangent of f(x)=(2/(x-2)),\at x=4 is y=-1/2 x+3