What is the integral of (2x-2x^2) ?

The integral of (2x-2x^2) is x^2-(2x^3)/3+C

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integral of (2x-2x^2)

\int (2 x - 2 x^{2}) d x

x^{2} - \frac{2 x ^{3}}{3} + C

Solution steps

\int 2 x - 2 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x d x - \int 2 x^{2} d x

\int 2 x d x = x^{2}

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

= x^{2} - \frac{2 x ^{3}}{3}

Add a constant to the solution

= x^{2} - \frac{2 x ^{3}}{3} + C

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