What is the integral of 4+x^2+sin(x) ?

The integral of 4+x^2+sin(x) is 4x+(x^3)/3-cos(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 4+x^2+sin(x)

\int 4 + x^{2} + sin (x) d x

4 x + \frac{x ^{3}}{3} - cos (x) + C

Solution steps

\int 4 + x^{2} + sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 d x + \int x^{2} d x + \int sin (x) d x

\int 4 d x = 4 x

\int x^{2} d x = \frac{x ^{3}}{3}

\int sin (x) d x = - cos (x)

= 4 x + \frac{x ^{3}}{3} - cos (x)

Add a constant to the solution

= 4 x + \frac{x ^{3}}{3} - cos (x) + C

\int (sin (x) + 1)^{2} d x

\int sin (n \cdot π \cdot x) d x

\int 8 t e^{- \frac{t}{5}} d t

\int i x d x

\int 8 x^{\frac{1}{3}} - 8 x^{- \frac{1}{3}} d x

What is the integral of 4+x^2+sin(x) ?
The integral of 4+x^2+sin(x) is 4x+(x^3)/3-cos(x)+C