What is the integral of sec(29w)tan(29w) ?

The integral of sec(29w)tan(29w) is 1/29 sec(29w)+C

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integral of sec(29w)tan(29w)

\int sec (29 w) tan (29 w) d w

\frac{1}{29} sec (29 w) + C

Solution steps

\int sec (29 w) tan (29 w) d w

Apply u-substitution

: \int \frac{1}{29} d u

= \int \frac{1}{29} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{29} u

Substitute back

u = sec (29 w)

= \frac{1}{29} sec (29 w)

Add a constant to the solution

= \frac{1}{29} sec (29 w) + C

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What is the integral of sec(29w)tan(29w) ?
The integral of sec(29w)tan(29w) is 1/29 sec(29w)+C