What is the integral of x\sqrt{x ?

The integral of x\sqrt{x is (sqrt(d)x^3)/3+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x\sqrt{x

\int x d x d x

\frac{d x ^{3}}{3} + C

Solution steps

\int x d x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= d \cdot \int xx d x

Simplify

xx : x^{2}

= d \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= d \frac{x ^{3}}{3}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{d x ^{3}}{3}

Add a constant to the solution

= \frac{d x ^{3}}{3} + C

\int \frac{17 x + 4}{3 x ^{2} - 7 x - 6} d x

\int 2 x - \frac{1}{5} d x

\int x e^{2 y} d x

\int x e^{- j w x} d x

\int \frac{e ^{x}}{1 - e ^{x}} d x