What is the integral of 1/(u^{5/4)}+6.5sqrt(u) ?

The integral of 1/(u^{5/4)}+6.5sqrt(u) is -4/(\sqrt[4]{u)}+4.33333…u^{3/2}+C

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integral of 1/(u^{5/4)}+6.5sqrt(u)

\int \frac{1}{u ^{\frac{5}{4}}} + 6.5 u d u

Solution steps

\int \frac{1}{u ^{\frac{5}{4}}} + 6.5 u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{u ^{\frac{5}{4}}} d u + \int 6.5 u d u

\int \frac{1}{u ^{\frac{5}{4}}} d u = - \frac{4}{u ^{\frac{1}{4}}}

\int 6.5 u d u = 4.33333 \dots u^{\frac{3}{2}}

= - \frac{4}{u ^{\frac{1}{4}}} + 4.33333 \dots u^{\frac{3}{2}}

Apply radical rule:

Add a constant to the solution

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What is the integral of 1/(u^{5/4)}+6.5sqrt(u) ?
The integral of 1/(u^{5/4)}+6.5sqrt(u) is -4/(\sqrt[4]{u)}+4.33333…u^{3/2}+C