What is the integral of (4e^{2x}-7e^{-x}) ?

The integral of (4e^{2x}-7e^{-x}) is 2e^{2x}+7e^{-x}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (4e^{2x}-7e^{-x})

\int (4 e^{2 x} - 7 e^{- x}) d x

2 e^{2 x} + 7 e^{- x} + C

Solution steps

\int 4 e^{2 x} - 7 e^{- x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 e^{2 x} d x - \int 7 e^{- x} d x

\int 4 e^{2 x} d x = 2 e^{2 x}

\int 7 e^{- x} d x = - 7 e^{- x}

= 2 e^{2 x} - (- 7 e^{- x})

Simplify

= 2 e^{2 x} + 7 e^{- x}

Add a constant to the solution

= 2 e^{2 x} + 7 e^{- x} + C

\int \frac{x}{x ^{2} + 4 x + 7} d x

\int sinh (8 - 9 x) d x

\int \frac{arcsin ( y )}{2} d y

\int y cos (x^{5}) d x

\int (2 e^{x} - 3 e^{- 2 x}) d x

What is the integral of (4e^{2x}-7e^{-x}) ?
The integral of (4e^{2x}-7e^{-x}) is 2e^{2x}+7e^{-x}+C