What is the integral of-4x^2ln(4x) ?

The integral of-4x^2ln(4x) is -4(1/3 x^3ln(4x)-(x^3)/9)+C

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integral of-4x^2ln(4x)

\int - 4 x^{2} ln (4 x) d x

- 4 (\frac{1}{3} x^{3} ln (4 x) - \frac{x ^{3}}{9}) + C

Solution steps

\int - 4 x^{2} ln (4 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \int x^{2} ln (4 x) d x

Apply Integration By Parts

: \frac{1}{3} x^{3} ln (4 x) - \int \frac{x ^{2}}{3} d x

= - 4 (\frac{1}{3} x^{3} ln (4 x) - \int \frac{x ^{2}}{3} d x)

\int \frac{x ^{2}}{3} d x = \frac{x ^{3}}{9}

= - 4 (\frac{1}{3} x^{3} ln (4 x) - \frac{x ^{3}}{9})

Add a constant to the solution

= - 4 (\frac{1}{3} x^{3} ln (4 x) - \frac{x ^{3}}{9}) + C

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What is the integral of-4x^2ln(4x) ?
The integral of-4x^2ln(4x) is -4(1/3 x^3ln(4x)-(x^3)/9)+C