What is the integral of 2xsin(1-x^2) ?

The integral of 2xsin(1-x^2) is cos(1-x^2)+C

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integral of 2xsin(1-x^2)

\int 2 x sin (1 - x^{2}) d x

cos (1 - x^{2}) + C

Solution steps

\int 2 x sin (1 - x^{2}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x sin (1 - x^{2}) d x

Apply u-substitution

: \int - \frac{sin ( u )}{2} d u

= 2 \cdot \int - \frac{sin ( u )}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 (- \frac{1}{2} \cdot \int sin (u) d u)

Use the common integral:

\int sin (u) d u = - cos (u)

= 2 (- \frac{1}{2} (- cos (u)))

Substitute back

u = 1 - x^{2}

= 2 (- \frac{1}{2} (- cos (1 - x^{2})))

Simplify

2 (- \frac{1}{2} (- cos (1 - x^{2}))) : cos (1 - x^{2})

= cos (1 - x^{2})

Add a constant to the solution

= cos (1 - x^{2}) + C

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What is the integral of 2xsin(1-x^2) ?
The integral of 2xsin(1-x^2) is cos(1-x^2)+C