What is the integral of 17e^u ?

The integral of 17e^u is 17e^u+C

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integral of 17e^u

\int 17 e^{u} d u

17 e^{u} + C

Solution steps

\int 17 e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 17 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 17 e^{u}

Add a constant to the solution

= 17 e^{u} + C

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