What is the integral of (x+1)/((x-1)(x-2)) ?

The integral of (x+1)/((x-1)(x-2)) is -2ln|x-1|+3ln|x-2|+C

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integral of (x+1)/((x-1)(x-2))

\int \frac{x + 1}{( x - 1 ) ( x - 2 )} d x

- 2 ln ∣ x - 1 ∣ + 3 ln ∣ x - 2 ∣ + C

Solution steps

\int \frac{x + 1}{( x - 1 ) ( x - 2 )} d x

Expand

\frac{x + 1}{( x - 1 ) ( x - 2 )} : \frac{x}{( x - 1 ) ( x - 2 )} + \frac{1}{( x - 1 ) ( x - 2 )}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x}{( x - 1 ) ( x - 2 )} d x + \int \frac{1}{( x - 1 ) ( x - 2 )} d x

\int \frac{x}{( x - 1 ) ( x - 2 )} d x = - ln ∣ x - 1 ∣ + 2 ln ∣ x - 2 ∣

\int \frac{1}{( x - 1 ) ( x - 2 )} d x = - ln ∣ x - 1 ∣ + ln ∣ x - 2 ∣

= - ln ∣ x - 1 ∣ + 2 ln ∣ x - 2 ∣ - ln ∣ x - 1 ∣ + ln ∣ x - 2 ∣

Simplify

= - 2 ln ∣ x - 1 ∣ + 3 ln ∣ x - 2 ∣

Add a constant to the solution

= - 2 ln ∣ x - 1 ∣ + 3 ln ∣ x - 2 ∣ + C

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What is the integral of (x+1)/((x-1)(x-2)) ?
The integral of (x+1)/((x-1)(x-2)) is -2ln|x-1|+3ln|x-2|+C