What is the integral of (\sqrt[3]{x^5}-2x+4) ?

The integral of (\sqrt[3]{x^5}-2x+4) is 3/8 x^{8/3}-x^2+4x+C

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integral of (\sqrt[3]{x^5}-2x+4)

\frac{3}{8} x^{\frac{8}{3}} - x^{2} + 4 x + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 2 x d x = x^{2}

\int 4 d x = 4 x

= \frac{3}{8} x^{\frac{8}{3}} - x^{2} + 4 x

Add a constant to the solution

= \frac{3}{8} x^{\frac{8}{3}} - x^{2} + 4 x + C

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What is the integral of (\sqrt[3]{x^5}-2x+4) ?
The integral of (\sqrt[3]{x^5}-2x+4) is 3/8 x^{8/3}-x^2+4x+C