What is the integral of 95-(3x^2+2x+10) ?

The integral of 95-(3x^2+2x+10) is -x^3-x^2+85x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 95-(3x^2+2x+10)

\int 95 - (3 x^{2} + 2 x + 10) d x

- x^{3} - x^{2} + 85 x + C

Solution steps

\int 95 - (3 x^{2} + 2 x + 10) d x

Simplify

= \int - 3 x^{2} - 2 x + 85 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 3 x^{2} d x - \int 2 x d x + \int 85 d x

\int 3 x^{2} d x = x^{3}

\int 2 x d x = x^{2}

\int 85 d x = 85 x

= - x^{3} - x^{2} + 85 x

Add a constant to the solution

= - x^{3} - x^{2} + 85 x + C

\int e^{2 x} sin (3 e^{2 x} + 1) d x

\int sin (6 θ) d θ

\int x + \frac{3}{x} d x

\int 3 x^{2} 2 x^{3} + 7 d x

tan (x^{2})

What is the integral of 95-(3x^2+2x+10) ?
The integral of 95-(3x^2+2x+10) is -x^3-x^2+85x+C