What is the integral of (x^4e^x-7x^3)/(x^4) ?

The integral of (x^4e^x-7x^3)/(x^4) is e^x-7ln|x|+C

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integral of (x^4e^x-7x^3)/(x^4)

\int \frac{x ^{4} e ^{x} - 7 x ^{3}}{x ^{4}} d x

e^{x} - 7 ln ∣ x ∣ + C

Solution steps

\int \frac{x ^{4} e ^{x} - 7 x ^{3}}{x ^{4}} d x

Expand

\frac{x ^{4} e ^{x} - 7 x ^{3}}{x ^{4}} : e^{x} - \frac{7}{x}

= \int e^{x} - \frac{7}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{x} d x - \int \frac{7}{x} d x

\int e^{x} d x = e^{x}

\int \frac{7}{x} d x = 7 ln ∣ x ∣

= e^{x} - 7 ln ∣ x ∣

Add a constant to the solution

= e^{x} - 7 ln ∣ x ∣ + C

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What is the integral of (x^4e^x-7x^3)/(x^4) ?
The integral of (x^4e^x-7x^3)/(x^4) is e^x-7ln|x|+C